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Simplify. Assume that no denominator is 0 and that 0^0 is not considered. (4x/3) ^3
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(4x/3)*(4x/3)*(4x/3) 4x * 4x * 4x 4*4*4*x*x*x ---------- = ------------ 3 * 3 * 3 3*3*3 can you do the rest?
Yes. I had (4x/3) ^3 4x *4x * 4x= 64x 3 * 3 * 3 = 27 64x/ 27 but I am unsure if this looks correct?
\[\left(\frac{4 x}{3}\right)^3\text{=}\frac{64 x^3}{27} \]
4*4*4 = 64 x*x*x = ??? 3*3*3 = ???
Thank you!!
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