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can we ever do this?
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no , that is actually log 4/2 = log 2
you get the same answer but you need to look at it as a division problem per se
HINT, \[\Large \log_a^b \to b \log a\]
o i kno tat. thankz
we can use, \[\large \frac{\log 4}{\log 2} \to \frac{\log 2^2 }{\log 2} \to \frac{2 \log 2}{\log2} \to 2\]
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