The sum of two natural numbers is 20. find the chance that their product will be less than 50?
do you consider 0 as natural number?
yes!
How many pairs of natural numbers add to 20?
21x21
let's see, there is 0+20 and 1+19 and 2+18 .... and 10+10
or i guess 21C2 .. if not repititive
then go through those 21 pairs and count how many of their products are less than 50
for now le't stick with 21 pairs
0 X 20 < 20, 1 X 19 < 20, ..... 10 X 10 > 20
21 for zero ... 20 for 1 ... 19 for two ...
then divide the number that multiply out > 20 by the number of pairs that add to 20 and that is the chance (probability) a minute ago
for 01 and 10 is counted as same
you need to look at natural numbers.... not digits
i meant ... 0x1 make one pair while 1x0 make another pair ... if they are counted as same then we need to omit it
I agree,I would only take the combinations into account, that's why I stopped at 10+10
14 for 3 ... 9 for 4 ... 5 for 5
3 for 6, 1 for 7 ... i guess rest are all used up
total we have 1+3+5+9+14+19+20+21 = 92
now it remains to determine how many unique combinations we can have for 21 numbers/
i guess ... 1+2+3+4+5+6+....+21 sample spaces that allows repetition and combinations
most likely answer will be 92/(1+2+3+ ,,,,, +21)
@philip513 @experimentX >>>>>> do you consider 0 as natural number? NO. The set of Natural numbers is the same as the set of positive integers. The set of Whole numbers includes 0 and the positive integers.
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