Question

Trigonometry. Rationalize the numerator. Assume that all radicands are nonnegative.

3+sin y/3-sin y (all under one square root)

Answer 1

thinking of multiplying both numerator and denominator by 3+siny? then change sin^2 to 1-cos^2, dunno

Answer 2

ohh sqrt() did not see that, let me write it down!

Answer 3

anyone helping?

Answer 4

trying to find some paper grr

Answer 5

Is this the problem
\[ \sqrt{\frac{3+sin(y)}{3-sin(y))} } \]

Answer 6

yes that's how it looks

Answer 7

Rationalize the numerator (normally people rationalize the denominator)
multiply top and bottom by sqrt(3+sin(y))

Answer 8

doing that, but i get to 3+siny/sqrt(cos^2x+8)

Answer 9

hmmm, think u need to do it like
sqrt\[((\sqrt(3+sinx)/\sqrt(3-sinx))*(\sqrt(3-sinx)/\sqrt(3-sinx))\]

Answer 10

so then is it sqrt() 9+sin^2/9-sin^2y ???

Answer 11

so u get to
\[\sqrt(9-\sin^2 x)/(3-\sin x)\]

Answer 12

that is it! this is the answer, no square root at the denominator