Question

When using nCr, how do you solve (1/3) C 1 ?

Answer 1

i dont think you can because , one factorials are only defined for positive integers, and two, 1 > 1/3 and n mustr be greater than r

Answer 2

I thought there was another formula for it. Because my teacher told me (1/3)C2 was (1/3((1/3)-1)/2!)

Answer 3

oh ok, i have never seen fractions used with combinations
i won't work on a calculator

Answer 4

it*

Answer 5

(1/3) C 1 =1/3

Answer 6

I'm pretty sure it's negative 1/3. But if it's like that, how would you do (1/2)
C 2?

Answer 7

no it's 1/3

but

(1/2) C 2=-1/8

Answer 8

Could you write up the equation for me please?

Answer 9

\[\binom \alpha k = \frac{\alpha(\alpha-1)(\alpha-2)\cdots(\alpha-k+1)}{k(k-1)(k-2)\cdots 1}\]

Answer 10

\[_\alpha C_k=\binom \alpha k\]

Answer 11

I understand the bottom part as a factorial, but how would you do the top part?

Answer 12

\[_{1/2}C_2=\frac{\frac{1}{2}\left(\frac{1}{2}-1\right)}{2(2-1)}=\frac{\frac{1}{2}\cdot\frac{-1}{2}}{2}=-\frac{1}{8}\]

Answer 13

how do you how many times you repeat the "(x-1)"? You said it was α(α−1)(α−2)....
but you only repeated 2 times above.

Answer 14

because k=2