Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (aravindg):

revision on integration and differentiation

OpenStudy (aravindg):

hey!

OpenStudy (aravindg):

shall we start

OpenStudy (accessdenied):

certainly

OpenStudy (anonymous):

follow this http://www.bbc.co.uk/scotland/learning/bitesize/higher/maths/calculus/

OpenStudy (aravindg):

1.Find the maximum value of the product of 2 nos if their sum is 12

OpenStudy (accessdenied):

So, we're maximizing "xy" if "x + y = 12"... I think if we rewrite the second equation with an independent variable, then we can clean up the first expression as a one-variable expression, and then find the horizontal tangent of that x + y = 12 y = 12 - x xy <- y=12-x x(12 - x)

OpenStudy (aravindg):

hmm then?

OpenStudy (accessdenied):

you can multiply it out and then take the derivative once you have the derivative, you set that equal to 0 to find the point of a horizontal tangent, since that will be the maximum (not really rigorous in showing that, but its an upside-down parabola so it has one horizontal tangent at the maximum point)

OpenStudy (accessdenied):

x(12 - x) = 12x - x^2 d/dx( 12x - x^2 ) = 12 - 2x 12 - 2x = 0 -2x = -12 x = 6 then we have to go back to that equation to find y's value y = 12 - x y = 12 - 6 y = 6 xy = 6(6) = 36

OpenStudy (aravindg):

wow thanks next one

OpenStudy (aravindg):

2 A printed page is required to contain k square units of printed matter .Side margins of width a and top bottom margins of width b are required .Find the length of the printed lines when the page is designed top use the least paper

OpenStudy (accessdenied):

is that all the information?

OpenStudy (aravindg):

ys

OpenStudy (accessdenied):

interesting... i'll have to think about that one a bit

OpenStudy (aravindg):

k post it here when u get an idea iw ill wait

OpenStudy (accessdenied):

|dw:1333259293620:dw| Well, since there's no numerical information given, i think the final answer isn't going to be a number, probably an expression with the k. That's the picture... hmm

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!