Question

I hope it doesn't seem like I'm asking a ton of questions, but I'm finishing up my geometry course and I have just a few more questions until I'm completely done!
Help with this question? Picture attached! :)

Answer 1

3y+4=11y
8y=4, y=1/2

Answer 2

hey take help from these
Let AB and AC be two tangent lines from a point A outside a given circle. Show?
that AB is congruent to AC.
How do I write the proof? Please help!


http://blog.csharphelper.com/2010/08/20/ …
Go to the web site above to see a picture of this problem.

A line which is tangent to a circle at a specific point is perpendicular to a line from the center of the circle to the same point.
The line from the center of the circle to the same point is a radius.


Lines AB and AC are the two tangent lines from a point A outside a given circle.

Let O = center point of the circle.
Lines OB and OC are the radius lines.


The 2 tangent lines, AB and AC, and the 2 radius lines, OB and OC, form a quadrilateral.

Angle ABO and angle ACO are right angles.
A line from the point A to point O divides the quadrilateral into 2 right triangles, ABO and ACO.

Line AO is the hypotenuse of both right triangles.

AB^2 + OB^2 = AO^2
AB^2 = AO^2 – OB^1


AC^2 + OC^2 = AO^2

AC^2 = AO^2 – OC^2

The radius lines, OB and OC, are equal length
So, OB^2 = OC^2.

So, AB = AC

Answer 3

the angle E and C are the same, so DE//AC. Therefore DBE and ABC are similar triangles. Let EC=x, then 32/48=28/28+x
then x=14, so BC=42