Question

Find dy/dx by implicit differentiation: 4 cos x sin y = 1

Answer 1

- 4 sin x sin y + 4 cos x cos y dy/dx = 0
=> dy/dx = sin x sin y/ cos x cos y = tan x tan y

Answer 2

use the product rule,,
\[-4sinxsiny+4cosxcosy \frac{dy}{dx}=0\]\[\frac{dy}{dx}=\frac{4sinxsiny}{4cosxcosy}=tanxtany\]

Answer 3

4cosxsiny=1
differentiate,
4[(cosx)(cosy)(y')+(siny)(-sinx)]=0
4(cosx)(cosy)(y')=4sinxsiny
(y')=4sinxsiny /4(cosx)(cosy)

Answer 4

thanks guyz