Ronald rode away from home in a car at the rate of 32mph . he walked back at the rate of 4 mph. the round trip required 2 hours and 15 minutes. how far did Ronald ride?

Question

inkyvoyd · Answer

Comon, we just did one of these for you!

anonymous · Answer

same idea as before

saifoo.khan · Answer

it's very similar.

saifoo.khan · Answer

Did you tried the question @Winnie846039137

anonymous · Answer

expression for time going is $\frac{d}{32}$ and expression for time returning is $\frac{d}{4}$ 
total time is 2 hours and 15 minutes aka $2\tfrac{1}{4}$ hours  set 
$$\frac{d}{32}+\frac{d}{4}=\frac{9}{4}$$ and solve for d

mathteacher1729 · Answer

This is the FIRST idea which will take some "meditation time":

$$ \Huge \text{Distance } = \text{ rate} \times \text{ time} $$

If you are waking at 4 miles per hour that means

4 miles = 1 hr
8 miles = 2 hrs
12 miles = 3 hrs 
etc. 

If you are driving 32 miles per hour that means

32 miles = 1 hr
64 miles = 2 hrs
96 miles = 3 hrs
etc.

This is the SECOND idea which will take "meditation time": 

You can find out how long it takes you to drive any amount of miles you like, by dividing both sides by the number of miles.

4 miles = 1 hour   
means
1 mile = 1/4 hours 

32 miles = 1 hour 
means
1 mile = 1/32 hours

You need to understand BOTH Of these ideas before the solutions given will make sense.

anonymous · Answer

one thing to be careful of is that the units you are given is miles and hours, so don't mess with the minutes
you want to write everything in terms of hours, which is why i wrote 
$$\frac{9}{4}$$ hours