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Mathematics 18 Online
OpenStudy (anonymous):

confuseddd!

OpenStudy (anonymous):

OpenStudy (anonymous):

i solved the problem and i got 31.98+0.877i but my online homework says that its wrong D:

OpenStudy (anonymous):

multiply the angle by 5!!

OpenStudy (mathteacher1729):

Is this a graded assignment?

OpenStudy (anonymous):

i did! look

OpenStudy (anonymous):

\[(r(\cos(\theta)+i\sin(\theta))^n=r^n(\cos(n\theta)+i\sin(n\theta))\]

OpenStudy (anonymous):

2^5(cos(5.pi/10)+isin(5.pi/10)

OpenStudy (anonymous):

ok so you have \[2^5(\cos(\frac{\pi}{2})+i\sin(\frac{\pi}{2}))\] right?

OpenStudy (anonymous):

32(cos1571)+isin(1.571)= 32(0.9996)+0.0274i=31.98+0.8768i

OpenStudy (anonymous):

so all you need now is \[2^5=32\] and \[\cos(\frac{\pi}{2})=?\]

OpenStudy (anonymous):

its pi/10 not 2

OpenStudy (anonymous):

put degrees out of your mind. you are working with numbers

OpenStudy (anonymous):

\[5\times \frac{\pi}{10}=\frac{\pi}{2}\]

OpenStudy (anonymous):

oh ! my bad

OpenStudy (anonymous):

now it is easy right?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

whew!

OpenStudy (anonymous):

haha thank you! i need help with finding the fourth roots of 256

OpenStudy (anonymous):

someone explained me but that's not what im looking for

OpenStudy (anonymous):

all four of them right?

OpenStudy (anonymous):

yeah like i know the last steps but i dont know to get to the equation, for instance i have this example that i did at school -8+8i , i dont know how to find the r and the angle to have the equation

OpenStudy (anonymous):

we can do it the snap way, first find all four roots of 1, then find the fourth roots of 256 one we know already, one fourth root of 256 is 4

OpenStudy (anonymous):

ok lets go slowly, but first note that finding the fourth roots of 256 in not like finding the roots of \(-8+8i\) because 256 is real

OpenStudy (anonymous):

oh yeah

OpenStudy (anonymous):

so all we have to do is find the fourth roots of 1, and then multiply each result by 4

OpenStudy (anonymous):

we get two right away, since \(4^4=256\) and also \((-4)^4=256\)

OpenStudy (anonymous):

which is like saying \(i^4=1\) and \((-1)^4=1\)

OpenStudy (anonymous):

do you know the other two fourth roots of 1?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

draw a unit circle, you know 1 is one answer so divide up in to 4 equal parts

OpenStudy (anonymous):

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OpenStudy (anonymous):

\[1^4=1,i^4=1,(-1)^4=1,(-i)^4=1\] there are the four answers \[\{1,i,-1,-i\}\] distributed evenly about the unit circle in the complex plane

OpenStudy (anonymous):

so if i want the 4 "fourth roots" of any number, take those four numbers and multiply by the positive real fourth root for example if i want the fourth roots of 81 i would instantly say: 3, 3i, -3, -3i

OpenStudy (anonymous):

why 3?

OpenStudy (anonymous):

oh never mind

OpenStudy (anonymous):

because \[3^4=81\]

OpenStudy (anonymous):

easy right?

OpenStudy (anonymous):

yes very haha but im still having problem with the other question the one of cos1/2 , it still says that its wrong

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