Question

A proton is acted on by an electric force of 3.2 x 10-14 N. What is the magnitude of
the electric field at the proton’s location? All answers in N/C

Answer 1

we have F=qE ,
where F is force on charged particle (in this case force on proton= 3.2*10^-14 N)
q is charge (in this case it is equal to 1.6*10^-19 C)
so, now by calculation,
E= 2*10^5 N/C

Answer 2

thank you for the help!

Answer 3

Welcome.. :)