If 125 of heat is applied to a 60.0- piece of copper at 21.0, what will the final temperature be?
\[\Delta Q=mc \Delta T\] This formula shows that the change in heat is equal to the mass times the specific heat times the change in temperature. You know the change of heat, the mass, and the initial temperature. So all you need to look up is the specific heat of copper and plug in your numbers.\[ \Delta X=X_{final} -X_{initial} \] Don't forget that triangle, Delta, means change. Change is just the final value minus the intial value. What's my change in age between 6 and 2 years old? 6 is my final age, 2 is my initial age, 6-2=4 years which is my change in age.
Make sure to always have units as well. 0.386Joules per gram C is coppers specific heat. \[{125J(g)(C) \over 60.0g(.386J)}=FinalC- 21.0C\]\[5.39C+21.0C= FinalC\]
26.39c
Yes ma'am.
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