Question

show that if you apply a particular factoring formula to 9x^2-4 that you get (3x-2)(3x+2)

How do I do this?

Answer 1

this is the difference of two squares
a^2 - b^2 = (a + b)(a - b)

Answer 2

so in your function a = 3x and b = 2

Answer 3

work it backwards to show that (3x-2)(3x+2)=9x^2-4
FOIL (3x-2)(3x+2)

Answer 4

I dont get it?

Answer 5

I'll try it...

Answer 6

always true?

?

Answer 7

always true for difference of 2 squares

Answer 8

Do i solve it as a equation?

Answer 9

no, just FOIL (3x+2)(3x-2), you will end up with 9x^2-4 because the -6x and the +6x cancel

Answer 10

a^2 = 9x^2 so a = 3x
b^1 = 4 so b = 2
now plug these values into the formula for a^2 - b^2

Answer 11

I dont get it!!

Answer 12

can someone explain this in a special ed term?

Answer 13

\[3x^{2}-2^{2}=(3x+2)(3x-2)\]