Question

Please help! If f^-1(x) exists, find this function algebraically.
f(x)=-x^3
f^-1(x)

Answer 1

rewrite to y=-x^3
to find the inverse, you'd replace x with y, y with x, and solve for y
x=-y^3
y^3=-x
y=(-x)^(1/3)=f^-1

Answer 2

Hmmm..
Here are my options though :/
a. does not exist
b. -x^3
c. =-1/x^3
d. -3\[\sqrt{x}\]

Answer 3

It keeps saying you're typing but nothing is showning up :/

Answer 4

*showing

Answer 5

Hello?

Answer 6

don't know what to tell you, f^-1(x)=-x^(1/3) is the inverse of f(x)=-x^3
you can show this by composition f(f^-1(x))=f^-1(f(x))=x

Answer 7

O.k. Thanks for your help Dockworker :)

Answer 8

f(x)=-x^3 and is a one-to-one function, so it's inverse is definitely a function

Answer 9

yw