Please help! If f^-1(x) exists, find this function algebraically.
f(x)=-x^3
f^-1(x)

Question

Please help! If f^-1(x) exists, find this function algebraically. 
f(x)=-x^3
f^-1(x)

anonymous · Answer

rewrite to y=-x^3
to find the inverse, you'd replace x with y, y with x, and solve for y
x=-y^3
y^3=-x
y=(-x)^(1/3)=f^-1

anonymous · Answer

Hmmm..
Here are my options though :/
a. does not exist
b. -x^3
c. =-1/x^3
d. -3$$\sqrt{x}$$

anonymous · Answer

|dw:1333333386770:dw|

anonymous · Answer

It keeps saying you're typing but nothing is showning up :/

anonymous · Answer

*showing

anonymous · Answer

Hello?

anonymous · Answer

don't know what to tell you, f^-1(x)=-x^(1/3) is the inverse of f(x)=-x^3
you can show this by composition f(f^-1(x))=f^-1(f(x))=x

anonymous · Answer

O.k. Thanks for your help Dockworker :)

anonymous · Answer

f(x)=-x^3 and is a one-to-one function, so it's inverse is definitely a function

anonymous · Answer

yw