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Mathematics 13 Online
OpenStudy (kymber):

Can you explain how to do this?!

OpenStudy (kymber):

OpenStudy (anonymous):

you mean tangent?

OpenStudy (anonymous):

tan(angle)

OpenStudy (anonymous):

use tangent

OpenStudy (anonymous):

or you can find hypotenuse and use pythagoreans

OpenStudy (anonymous):

no.. use tangent or cotangent \[\Large \tan(63^{\circ})=\frac{14}{x} \] if I made a mistake, someone correct me

OpenStudy (anonymous):

^ that's correct

OpenStudy (anonymous):

\[H=14\div \tan 63\] find H...

OpenStudy (anonymous):

\[\LARGE H\approx 7.13\]

OpenStudy (kymber):

So is the answer 7.1? How do you know to do this? I don't get it

OpenStudy (anonymous):

They are correct! :)) By using the tangent. :))

OpenStudy (saifoo.khan):

My bad. i thought 14 is hypotenuse. kill me,

OpenStudy (anonymous):

\[\Large \tan x=\frac{\sin x}{\cos x}\] \[\Large \tan x=\frac{14}{H}\Longrightarrow \frac{\sin x}{\cos x}=\frac{14}{H}\] use cross multiply and you'll get... \[\Large {H\cdot \sin x}={14\cdot \cos x}\] divide both sides by sin x ... \[\Large H=\frac{14\cdot \cos 63^{\circ}}{\sin 63^{\circ}}\] now use calculator .. and you'll get the result.. \[\LARGE H\approx 7.13\]

OpenStudy (anonymous):

will do ... jking

OpenStudy (anonymous):

what does it mean jking @Outkast3r09 ? :$

OpenStudy (anonymous):

was talking to saifoo lol

OpenStudy (anonymous):

just kidding

OpenStudy (anonymous):

I apologize... Have a nice day ;)

OpenStudy (kymber):

Thaanks!! :D

OpenStudy (anonymous):

Glad to help :)

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