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OpenStudy (kymber):
OpenStudy (anonymous):
you mean tangent?
OpenStudy (anonymous):
tan(angle)
OpenStudy (anonymous):
use tangent
OpenStudy (anonymous):
or you can find hypotenuse and use pythagoreans
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OpenStudy (anonymous):
no.. use tangent or cotangent \[\Large \tan(63^{\circ})=\frac{14}{x} \]
if I made a mistake, someone correct me
OpenStudy (anonymous):
^ that's correct
OpenStudy (anonymous):
\[H=14\div \tan 63\] find H...
OpenStudy (anonymous):
\[\LARGE H\approx 7.13\]
OpenStudy (kymber):
So is the answer 7.1? How do you know to do this? I don't get it
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OpenStudy (anonymous):
They are correct! :)) By using the tangent. :))
OpenStudy (saifoo.khan):
My bad. i thought 14 is hypotenuse. kill me,
OpenStudy (anonymous):
\[\Large \tan x=\frac{\sin x}{\cos x}\]
\[\Large \tan x=\frac{14}{H}\Longrightarrow \frac{\sin x}{\cos x}=\frac{14}{H}\]
use cross multiply and you'll get...
\[\Large {H\cdot \sin x}={14\cdot \cos x}\] divide both sides by sin x ...
\[\Large H=\frac{14\cdot \cos 63^{\circ}}{\sin 63^{\circ}}\]
now use calculator .. and you'll get the result..
\[\LARGE H\approx 7.13\]
OpenStudy (anonymous):
will do ... jking
OpenStudy (anonymous):
what does it mean jking @Outkast3r09 ? :$
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