Question

4=√-2

a.√6
b.36
c.3
d.6

Answer 1

is there x to find or anything...???

square both sides...

Answer 2

i thought u cant have negatives under a radical

Answer 3

if there's no x or something ... they are not equal !

Answer 4

it can't be solved, coz sq. root having a negative sign is undefined

Answer 5

i meant 4=√p-2

Answer 6

@tsitrond actually you can, is just that you have to do with complex numbers!! Example...

\[\LARGE \sqrt{-25}=i\cdot 5\]

Answer 7

then square both sides and you'll get

16=p-2

p=16+2


unless 2 is not under the square isn't it??

Answer 8

\[4+2=\sqrt{p}\]
6=\[\sqrt{p}\]

Answer 9

@kreshnik yes i know but that is unreal numbers... i assumed this was all real numbers situation