Evaulate the indefintie integral will post
\[\int\limits_{}^{} \sec ^{5}(3x ^{2}) \tan (3x ^{2})x dx\]
look in your text for the reduction formula for tangent and secant split in to \[\int\sec^3(3x^2)\tan(3x^2)\sec^2(3x^2)dx\] then use \[u=\tan(3x^2), du =6x\sec^2(3x^2)dx\]
i think you lost an x
than and that still leaves the sec^3 (3x^2)
@satellite73
I'm not sure if it is correct...
@Callisto i cant read the last part of the third line with the equation mark
First few lines only
i am an idiot \[u=\sec(x), du =\sec(x)\tan(x)dx\]
get \[\int \sec^4(x)dx\] and done in one step sorry about original post
@satellite73 You're too hard on your self.
ok i got it annd i agree brainshot you kinda are
i hate techniques of integration lot of show off nonsense
* no one understand my workings.. poor me *
lol
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