look in your text for the reduction formula for tangent and secant
split in to
\[\int\sec^3(3x^2)\tan(3x^2)\sec^2(3x^2)dx\] then use
\[u=\tan(3x^2), du =6x\sec^2(3x^2)dx\]
OpenStudy (anonymous):
i think you lost an x
OpenStudy (anonymous):
than and that still leaves the sec^3 (3x^2)
OpenStudy (anonymous):
@satellite73
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OpenStudy (callisto):
I'm not sure if it is correct...
OpenStudy (anonymous):
@Callisto i cant read the last part of the third line with the equation mark
OpenStudy (callisto):
First few lines only
OpenStudy (anonymous):
i am an idiot
\[u=\sec(x), du =\sec(x)\tan(x)dx\]
OpenStudy (anonymous):
get
\[\int \sec^4(x)dx\] and done in one step
sorry about original post
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OpenStudy (anonymous):
@satellite73 You're too hard on your self.
OpenStudy (anonymous):
ok i got it annd i agree brainshot you kinda are
OpenStudy (anonymous):
i hate techniques of integration
lot of show off nonsense