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Mathematics 9 Online
OpenStudy (anonymous):

On an examination, a student is to select any 4 questions out of 7 to answer. a. How many different sets of 4 questions can be selected? b. How many sets of 4 questions will include question 1? c. If a student answers 4 questions out of 7 on a test, what is the probability that he selected question1?

OpenStudy (inkyvoyd):

a. 7C4 b. 4/7 times total c. wow.

OpenStudy (anonymous):

\(\dbinom{7}{4}=35\)

sam (.sam.):

@satellite73 you're good at statistics :)

OpenStudy (anonymous):

\[\dbinom{6}{4}=15\] for the second one

OpenStudy (anonymous):

i know absolutely no statistics sorry

OpenStudy (inkyvoyd):

EMPIRICAL RULE FTW FTW

OpenStudy (inkyvoyd):

EVEN CALCULUS HATES THE ERF()

OpenStudy (anonymous):

what's c? I know it's not 0...

OpenStudy (anonymous):

if question one is selected, then so are three out of the other 6 so answer i s \[\frac{\dbinom{6}{3}}{\dbinom{7}{4}}\]

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