Question

What is the length of the conjugate axis?

(x-2)^2/(36) - (y+1)^2/(64) =1

Answer 1

had to chk to be sure; the number in the denom of your - term; sqrt it, what do we get?

Answer 2

if they are going to call them a transverse and a conjugate axis they might as well define the generic as:
\[\frac{x^2}{t^2}-\frac{y^2}{c^2}=1\]

where the c^2 is always under the - part

Answer 3

so you're referring to C^2 which happens to be 64 in the equation

Answer 4

?

Answer 5

2 * 8 = 16