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Mathematics 22 Online
OpenStudy (anonymous):

How many extrema (maxima and minima) does the function f(x) = (x+2)^3 * (x-5)^2 have? PS...no calculator allowed for this question or else i would've just graphed it

OpenStudy (anonymous):

Take the derivative and set it equal to zero, take that answer and plug it into the second derivative, if it is negative, then it is a maxima and if it is positive, then it is a minima.

OpenStudy (anonymous):

im not sure how to differentaite that

OpenStudy (anonymous):

Product rule. 3(x+2)^2 * (x-5)^2 + 2(x-5)*(x+2)^3

OpenStudy (anonymous):

how wud i possibly solve taht for 0?

OpenStudy (anonymous):

can that be simplified or smthng

OpenStudy (anonymous):

Ha yeah I guess that seems a bit tough. If you have a calculator you can type it in and find where y=0 to find the answers. If not then you will have to do it the long way.

OpenStudy (anonymous):

Ok I think you need to be able to see this typed as an equation without the little "^" signs... http://www.wolframalpha.com/input/?i=3%28x%2B2%29^2+*+%28x-5%29^2+%2B+2%28x-5%29*%28x%2B2%29^3%3D0 you ca factor out (x+2)^2 and (x-5) which should make the equation a lot easier to solve.

OpenStudy (anonymous):

im not sure how it simplified into (x-5)*(x+2)^2 * (5x-11)...idk where the 3rd part comes from

OpenStudy (anonymous):

Do you remember the product rule?

OpenStudy (anonymous):

yeah f'g +fg' / g^2

OpenStudy (anonymous):

Wait, where did you get (5x-11) from??

OpenStudy (anonymous):

tahts wat wolframalpha says

OpenStudy (anonymous):

No, that's the quotient rule, that would be if you are dividing, well no actually you would need to have f'g - fg' / g^2 for the quotient rule. The product rule is just f'g +fg'

OpenStudy (anonymous):

is an alternate form of it...im assuming tahts wat it is simpleied

OpenStudy (anonymous):

Oh, no you are looking at the "alternate forms" that is because it is simplified. Just look at the main equation at the top.

OpenStudy (anonymous):

oh ok so x=5 or x = -2 then

OpenStudy (anonymous):

Yes!

OpenStudy (anonymous):

but when i do s sign diagram i get only one maxima but the asnwer is 2 maximas

OpenStudy (anonymous):

Never mind i get it wen i llok at the graph.

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