Question

Write the following polynomial as products of linear factors.

9z^2-6z+5

Answer 1

@.Sam.

Answer 2

it is not factorable :(

Answer 3

The answer is (3z-1-2i)(3z-1+2i)... but how to get there?

Answer 4

Try using the QUADRATIC FORMULA. :))

Answer 5

Can u see if you get the answer?

Answer 6

Set the function equal to zero. Find the roots(using that discriminant formula). If the roots are a,b then the function can be rewritten as:
\[(z-a)(z-b)\]
I get\[(a,b)=(6\pm \sqrt{36-180})/18\]

Answer 7

Which comes out as\[ 1\pm2i \over 3\]

Answer 8

How does 3 become 3z and 1 become -1?

Answer 9

\[a=(1+2i)/3; b=(1-2i)/3\]
\[(z-(1+2i)/3)(z-(1-2i)/3)=0\]
Multiply this by 3

Answer 10

Thanks :)