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find dy/dx if y= (cos x)^x
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hmm
method one take the log use property of log to simplify take the derivative using the product rule and the chain rule multiply by the original function method two write \(\cos(x)^x\) as \(e^{x\ln(\cos(x))}\) and take the derivative using the chain rule the work is identical
I guess I've seen this question today.. y= (cos x)^x Take ln on both sides ln y = x ln cosx Diff both sides w.r.t. x (1/y) dy/dx = x (1/cosx) (-sinx) + lncosx dy/dx = y(- xtanx + lncosx) = cosx^x (lncosx-xtanx ) It should be something like this :S
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