In a single-slit diffraction pattern, the distance between the first and second minima is 1.8cm on a screen 4.4m from the slit. Find the slit width given that the wavelength of the light is 550nm.

Question

ash2326 · Answer

@Mythias it won't help much posting this here. Please post this in Physics. Thanks:)

anonymous · Answer

its just that the physics forum is dead....lol
plus ive always gotten more help here LOL

callisto · Answer

First, you should put this question in the Physics group.
Second, slit width = λD/a , if you remember it correctly

callisto · Answer

sorry , you -> I :S

experimentx · Answer

seems like double slit interference

callisto · Answer

that would be dsinθ = mλ, i believe

anonymous · Answer

ya the formulas u guys have r correct

experimentx · Answer

that looks like bragg's law ... if you add 2 on lhs ...

anonymous · Answer

do we do 
y=mlamdaL/d?

callisto · Answer

sorry i remember that wrong :S
fringe separation = λD/a, a is the slit separation, d is the distance from the screen ...

callisto · Answer

1.8/100 = ( 550x10^-9 )  (4.4) /a
a =  ( 550x10^-9 )  (4.4) / 0.018

experimentx · Answer

yeah you are right .. same as iterference comes form here http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/imgpho/ymin2.gif

callisto · Answer

I don't like doing these king of question, i mixed the formulas up or can't remember the unknowns well :S

callisto · Answer

*kind

anonymous · Answer

thanks guys :)