A company installs 5000 light bulbs, each with an average life of 500 hours, standard deviation of 100 hours, and distribution approximated by a normal curve. Find the percentage of bulbs that can be expected to last the period of time. Less than 690 hours A. 97.06% B. 47.14% C. 97.1% D. 97.2%
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690-500 is the distance we are from the mean 190 ; we want to measure this against the standard rule of the deviation; so divide this bu the standard deviation 190/100 = 1.9 this value is called a zscore, or a standard score and tells us how many standard deviations we are from the mean
we look this number up on a ztable; .... plit it into left and right parts tho: 1.90 = 1.9 and .00|dw:1333483648431:dw|
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