Question

∫√(1+(e powered by 2)dx

Answer 1

\[1+e^2\]

Answer 2

?

Answer 3

e to the x

Answer 4

you're missing a square root

Answer 5

cambell

Answer 6

the contents are enclosed in a root sing

Answer 7

then its even easier as
\[\sqrt{1 + e^2}\]

is a constant

\[\int\limits \sqrt{1 + e^2} dx = x \sqrt{1 + e^2} + c\]

Answer 8

help me guys

Answer 9

how do i then work it out

Answer 10

^ what cambell said. you have a constant unless that last part is e^2x then you have something different

Answer 11

its actually e raised to x

Answer 12

not to 2

Answer 13

well \[\sqrt{1 + e^2} = 2.896\]

its just a number.... you can plot it on the number line

the the problem is just like

\[\int\limits 5 dx = 5x + c\]

Answer 14

\[\int\limits_{}^{}\sqrt{1+e ^{x}}\]

Answer 15

lol... now you have the question

\[\int\limits \sqrt{1 + e^{2x}} dx\]

Answer 16

only x not 2x

Answer 17

dnt leave yet campbell i could really use your help with a couple qsns

Answer 18

is it goin well

Answer 19

well then its integration by substitution

let u = e^x du/dx = e^x du = e^xdx or dx = du/u



\[\int\limits \sqrt{(1 + u)}/u du\]

looks like a double substitution... good luck

Answer 20

what then would be the final answer ?

Answer 21

\[u=1+e^x\]