Question

Geometry help please!

Answer 1

please help me

Answer 2

should we assume that 'x' is the length of the altitude to the hypotenuse? If so, we only need to take the geometric mean of the hypotenuse segments
x 9
- = -; for x
5 x

Answer 3

I don't get it. x would =1.3

Answer 4

in the triangle, we have a 45-45-90 triangle. do you know how the legs of that triangle compare to the hypotenuse?

Answer 5

what would be the answers?

Answer 6

im not here to give you the answer, just help you get there. :(

Answer 7

what you are saying doesnt make sense

Answer 8

If this is what we know in the triangle, the last angle is 45, right? So, since the two angles are congruent, the legs are also congruent (isosceles triangle th). Pythagorean theorem to find the hypotenuse would be:
a^2 + a^2 = h^2
2a^2 = h^2
sqrt(2a^2) = sqrt(h^2)
a*sqrt(2) = h
this is true for all 45-45-90 triangles with a side length "a" and hypotenuse "h"

Answer 9

5(5)+5(5)=h(h)

Answer 10

yes, 5*5 + 5*5 = h^2 (although h is y in the context of our problem)

Answer 11

ok next it would be 2(5)*5=h*h

Answer 12

it is 50

Answer 13

yeah, you could do that
50 = h*h , then you take the positive square root of both sides (h*h = h^2)

Answer 14

the answer is b?

Answer 15

Yes. :)

Answer 16

can you help me on #1?

Answer 17

the first problem you posted? well, when we have an altitude that divides the opposite hypotenuse, it divides them in a way that we can set up certain ratios between the triangles.


Basically, we set it up as
\[ \frac{5}{x} = \frac{x}{9} \]
In words, we take the left hypotenuse segment (5) over the altitude (x) and set it equal to the altitude (x) over the right hypotenuse segment (9).
that's not the only way to write it necessarily, but I'll go with this way. they all work. then solve for x