Question

im not sure that my answer is correct, please review!

Answer 1

i think -6

Answer 2

1/64 = 2^-6

Answer 3

The answer should be -6

Answer 4

not quite.. log works like this:

\[\text{if } 2^5 = 32\text{ , then }\log_2(32) = 5\]

Answer 5

why is it negative and not positive 6?

Answer 6

so:
\[2^{-6} =\frac{1}{64} \text{ so } \log_2{(\frac{1}{64})} = -6\]

Answer 7

remember:

\[x^{-a} = \frac{1}{x^a}\]

Answer 8

why cant i just put a positive 6? its confusing me

Answer 9

It wouldn't be a fraction

Answer 10

\[2^6 = 2 \times 2 \times 2 \times 2 \times 2 \times 2\]\[2^{-6} = \frac{1}{2^6}\]