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Chemistry 11 Online
OpenStudy (anonymous):

2mL of I2/KI aqueous solution and 2 mL of varsol are added. These two are immiscible, so they form two layers. 2 drops of sodium thiosulphate are added to this. What happened was that Phase A (varsol) turned lighter than control (pink), and Phase B (I2/KI) turned lighter than control (yellow)

OpenStudy (anonymous):

So, why did this happen when taking into account the chemistry perspective?

OpenStudy (anonymous):

I figured out.

OpenStudy (anonymous):

I'm not sure about the varsol but i do know the thiosulfate reduces the iodine in solution to iodide which is why b goes clear.

OpenStudy (anonymous):

2 S2O32−(aq) + I2(aq) → S4O62−(aq) + 2 I−(aq)

OpenStudy (anonymous):

Wikipedia FTW

OpenStudy (anonymous):

This occurred in both solutions, and I interpreted it from there.

OpenStudy (anonymous):

Ok could you help me with the last question I have.

OpenStudy (anonymous):

It is this:

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

You have this solution: Put 5 mL of 0.1M magnesium chloride into a test tube. Add 5mL of 1M ammonium solution. Shake to mix and observe. Add 1g of ammonium chloride and shake well. Observe again What are the possible reactions and/or equilibria that can be taking place here?

OpenStudy (anonymous):

This is what I got so far: NH3(aq) + H2O(l) <=> NH4+(aq) + OH-(aq) ^- because it was an aqueous solution of NH3(aq) <-- I forgot to mention that.

OpenStudy (anonymous):

and then there is NH3, Mg, Cl NH3 + MgCl2 --> NO REACTION?

OpenStudy (anonymous):

Professor's reply: I can suggest that you consider what other possible products could be made from the combination of ions that you have present in your solution(s). You are missing some key reactions/equilibria in your analysis.

OpenStudy (anonymous):

He probably means MgOH2. Becuase when NH3 goes into water it will form NH4 and OH ions. Which means that MgOH2 will probably form with NH4Cl added. I'll come up with a link or better answer.

OpenStudy (anonymous):

is magnesium hydroxide a slighty soluble comp/ d

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Yes it is

OpenStudy (anonymous):

\[Mg^{2+}_{(aq)} + 2NH^3_{(aq)} + 2H_2O_{(l)} <==> Mg(OH)_{2(s)} + 2NH4^+_{(aq)}\]

OpenStudy (anonymous):

then on addition of NH4 you can see how it would shift left and the ppt will dissolve

OpenStudy (anonymous):

It will shift left due to common ion NH3?

OpenStudy (anonymous):

because I had: NH3(aq) + H2O(l) <=> NH4+(aq) + OH-(aq)

OpenStudy (anonymous):

SORRY

OpenStudy (anonymous):

Common ion NH4+

OpenStudy (anonymous):

Common ion NH4+

OpenStudy (anonymous):

Yeah.

OpenStudy (anonymous):

The equation i gave you will be the first one your professor is looking for. Now just say that on addition of excess NH4+ from the ammonium chloride that the precipitate will dissolve due to le chatlier's principal.

OpenStudy (anonymous):

So does that make sense QRA?

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