Question

HELP WITH CALCULUS WORD PROBLEM

Answer 1

The amount of radiation, R(t) in a certain liquid decreases at a rate proportional to the amount the amount present, that is dR/dt= kR, where k is a constant & t is measured in seconds. The initial amount of radiation is 10^6 rads. After 100 secs the radiation has dropped to 10^2 rads.

Answer 2

a) Express R as a function of t
b) To the nearest sec, when will the amount of radiation drop below 10 rads?
c) What is the half-life of this chemical? That is, how long does it take for the amount of radiation to reach the half life of the original amount?

Answer 3

R(t) = 10^6*e^(kt), where k = (-4ln10)/100
that's part a.

Answer 4

like how did u get taht value for k