Question

Anyone good at condensing logarithms?

Answer 1

We all are.

Answer 2

Step 1 is the original problem. Step 2 is as far as I've gotten.

Answer 3

in step 2, there should be an 'x' between the 2 and the 1/2. I forgot to add it.

Answer 4

hmmm. first thing..write the variables correctly..you're making them look like exponents..they should be on level with the word "log"

second...start by finding all the ones with the same bases...all have the same bases so you're good. next step is to combine the additions..multiply them..can you do that?

Answer 5

\[\frac{1}{2}\log_{2}x-4\log_{2}y+e \log_{2}z=\log_{2}x ^{\frac{1}{2}}-\log_{2}y^4+\log_{2}z^e \]

Answer 6

well, I have to work left to right, so wouldn't the be combining the subractions first?
The poperty would be logb (M/N)

Answer 7

*property

Answer 8

\[\log_{2}x^\frac{1}{2}z^3-\log_{2}y^4=\log_{2}\frac{x^\frac{1}{2}z^e}{y^4} \]

Answer 9

how did you get the first one?

Answer 10

Who are you talking to?

Answer 11

You, sorry. Mertsj

Answer 12

The first one what?

Answer 13

the log2x1/2^3 - sorry, I do'nt know how to write it in the correect form like you did

Answer 14

by usisng the property that log m + log n = log mn

Answer 15

Product Law @culinarychick and it's z^w @Mertsj you misread your previous solution ^_^

Answer 16

z^e

Answer 17

Ok. Too many cooks spoil the broth. Good bye.

Answer 18

but since I have to work left to the right, wouldn't I use the subtraction property first? logb(M/N)?

Answer 19

hahaha =)))

Answer 20

she just did it all at once @culinarychick makes no difference :)

Answer 21

oh ok! I just have to show each and every step in my homework - my professor is anal. if I miss a single step, he'll take off points. That's why I was confused!

Answer 22

Addition is commutative. You can change the order of the addends if you want to.