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find the derivative of y with respect to x in y=sin^(-2)(x^3)
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-2Sin(x^2) * 2x
* Cos (x^2) <= forgot that part
Answer is -6x^2cosx^3/ sin^3x^3
is the (-2)(x^3) all in the exponent?
\[Sin ^{-2}x ^{2}\]??
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\[\sin^{-2} x^3\]
Answer is \[-6x^2cosx^3/\sin^3x^3\]
i think that there should be an x after the sin?!?!?!?
Nope.
wierd! hold on!
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derivative of sin^(-2)(x^3) = -2 * 3x² sin^(-3) x³ * cos x³ = - 6x² cos x³ / sin³ x³
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