Question

Find two consecutive positive integers such that the square of the second is added to 6 times the first is equal to 49?????

HELP PLEASE

Answer 1

trouble setting it up?

Answer 2

what should the formula look like?

Answer 3

well, there are two numbers to look for...
so two variables... which means you need two equations to solve it

Answer 4

let X be the first number and Y be the second number, can you dig an equation out of that sentence?

Answer 5

X and Y are consecutive integers. What does that mean in terms of X and Y? X = what?

Answer 6

Let x be a positive integer. Then, x +1 is the next consecutive positive integer

6x + (x+1)^2 = 49
6x + x^2 + 2x + 1 = 49
x^2 +8x -48 =0
(x +12)(x- 4)=0
Zero Product Property
x = -12 and x = 4
Integers must be positive so -12 is not considered.

Answer: 4 and 5

Answer 7

thank you