Question

In a simple Atwood machine, the masses are released from rest and accelerate at a rate a. If the radius of the pulley is r, through what angle does the pulley rotate in time t after the masses are released?

a) (ra)/t
b) (ra)/(2t^2)
c) (at)/r
d)(at^2)/(2r)

Answer 1

\[a=\alpha \times r\]
This is the relation between linear acceleration a and angular acceleration alpha. Find alpha. Then use this to find angular distance
\[\theta=\alpha timest ^{2}/2\]
ok?

Answer 2

@maniwould that make it d?

Answer 3

@mani_jha

Answer 4

Yes.

Answer 5

thanks