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find the vertices and foci of the hyperbola: Y^2/5-X^2=1
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The foci of this hyperbola are found using the Pythagorean Theorem \[a^2+b^2=c^2\] Whereas the vertices of the parabola are given as \[(0,\pm a)\] The equation of this hyperbola follows the form \[\frac{y^2}{a^2}-\frac{x^2}{b^2}=1 \] Can you solve the problem now?
not really i need further explaining
What didn't you understand?
what # to put where
OK, so the equation is \[\frac{y^2}{5}-x^2=1\] equivalent to \[\frac{y^2}{5}-\frac{x^2}{1}=1\] so \[a^2=5, b^2=1\]
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