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find k such that f(x)=x^3-kx^2+kx+6 has the factor x-2
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If x-2 is a factor of f then f(2)=0
So use this f(2)=0 to find k
what the question is asking is to find the value of k
So you got it @Sona ?
thanks
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If you want to put your answer, I will check it
i'm stuck
so far i'm @ -2k^2+2k+14=0
\[f(2)=0=2^3-k(2)^2+k(2)+6\]
hmmm... I don't see any k squared in your problem \[0=8-k(4)+2k+6\] \[0=8-4k+2k+6\]
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\[0=8-2k+6 \]
You can finish the rest I believe right?
so k shud equal 7?
ya thats correct thank you!!!
yes lol that is right I agree with your homework checker
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