Question

If 62.7 g N2 react with 23.8 g H2 according to the reaction below, how many grams of ammonia (NH3) can be produced, and how many grams of the excess reactant will be left over?

Unbalanced equation: N2 + H2 → NH3

Answer 1

see u need to know the concept of limitting reagent. i assume u know it. if u dont then tell me ok. i will explain.
step. write the balanced eqn N2 + 3H2 → 2NH3
now calculate the moles of given gases.
moles of N2=4.478
moles of H2=11.9
now use unitary method
1 mole of N2 requires 3moles of H2
4.478 moles will require 4.478 X 3= 13.343
so u can see that u dont have sufficient H2. so H2 is ur limitting reagent.
now again
3 moles of H2 produce 2 moles of NH3
so 11.9 will produce 11.9X2/3=3.12 moles.
thanku

Answer 2

reply me if answer was satisfactory