Question

can someone help me w/ this problem


f(t)= 5000/1+50e^-0.4t

a. approximately how many people will have heard the news after 8 days?

b. how long will it take for half of the townspeople to have heard about the meeting?

c. find an equation to express the rate at which notice of the meeting is spreading

Answer 1

f(t)= 5000/(1+50e^-0.4t)

Answer 2

is the unit of t day?

Answer 3

= 134

Answer 4

@uh_oh_boy23 I believe your post's sort of chop off head and tail!

Answer 5

what do u mean?

Answer 6

yes expx

Answer 7

heres the rest Notice of a town meeting is spread by word of mouth to the town's 5000 residents. After t days, the number of people who know about the meeting is expressed by the function

Answer 8

the beginning

Answer 9

b) Half of town ...?
There's no data about the number of the whole town?

Answer 10

for your first proble, put 8 inplace of t and calculate it's vlaue

Answer 11

i think the whole town people is 5000

Answer 12

f(8)= 5000/(1+50e^-0.4(8)) = 5000 / (1+50e^-3.2)
Can you do the calculation yourself?

Answer 13

@experimentX it's 5000 as '' the town's 5000 residents''

Answer 14

(b)
f(t) = 5000/2 = 5000/(1+50e^-0.4t)
2500 = 5000/(1+50e^-0.4t)
2 = (1+50e^-0.4t)
Can you solve it from here?

Answer 15

yeah .. my language mistake

Answer 16

i think for the last part ... you just need to differentiate the function with respect to t

Answer 17

ok

Answer 18

so for like A plug in 8 for t?

Answer 19

c) f'(t) = 10.000 e^ (- .04t) / [ 1 + 50 e (- .04t) ]²

Answer 20

Why don't you give a try on a) and b)