Need explanation pleaase!
Find the equation of the tangent line to the given curve at the given point.
Can someone please explain?

Question

Need explanation pleaase! 
Find the equation of the tangent line to the given curve at the given point. 
Can someone please explain?

anonymous · Answer

$$y = 1/cosx - 2cosx $$

roadjester · Answer

To find the tangent line, you must first find the derivative.

anonymous · Answer

given point is ( pi/3 , 1) and answer is 3$$3\sqrt{3x}-y+1-\pi \sqrt{3}=0 $$

roadjester · Answer

Then use the point-slope formula

anonymous · Answer

Can you show me?

roadjester · Answer

I'm sorry, I have to go...I'll be free tomorrow.

experimentx · Answer

find the derivative, put the values, you will get the slope
since you have point and slope ... use single point slope formula

anonymous · Answer

Okay thanks:D but the problem is I keep getting the answer wrong.

anonymous · Answer

y = 1/cosx−2cosx
y = - sinx/ cox²x + 2 sinx

anonymous · Answer

f (x) = - tanx/ cosx + 2sinx
f ( pi/3) = -2√3  +  √3    = - √3

anonymous · Answer

Tangent line at ( pi/3 , 1) :
y - 1 = -√3 ( x - pi/3)
=> y = -√3 x + pi/√3

anonymous · Answer

@bobobo  Not sure if your post miss some parentheses!