Question

In Radians:

Answer 1

sin (Arc sec 4)

Answer 2

Please walk me through how you would approach solving this

Answer 3

Anyone?

Answer 4

so basically you want the answer to this: \[\sin(\sec ^{-1} (4))\]?

Answer 5

Well, there are no calculators allowed, so it has to be a special triangle....

Answer 6

sec A = hypotenuse/ base

which means sin(arcsec(4)) => sin(arcsec(4/1)) => h =4, b =1
now sin of same anlge = p/h => sqrt(4^2-1)/4 => sqrt(15)/4

Answer 7

Thanks - that makes sense!