Question

completing the sqaure of 0.5g^2+8g=-7 show work plez?!?

Answer 1

multiply everything by 2 first of all
g^2+16g=-14
take half of 16, which is 8, and square it. then add to each side
g^2+16g+64=-14+64
(g+8)^2=50
if you want to solve, take square root of each side:
\[g+8= \pm \sqrt{50}\]
\[g+8= \pm 5\sqrt{2}\]
\[g=-8 \pm 5\sqrt{2}\]

Answer 2

double each term

g^2 + 16g = -14

for a quadratic ax^2 + bx + c = 0

find (b/2)^2 (16/2)^2 = 64

you need the constant to equal 64

g^2 + 16g + 14 + 50 = 0

(g + 8)^2 = 0

Answer 3

oops (g +8)^2 = 50