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Mathematics 14 Online
OpenStudy (anonymous):

An item costs $500 at time t=0 and costs $P in year t. When inflammation is r% per year, the price is given by P = 500e^(rt/100) a) if r is a constant, at what rate is the price rising ( in dollars per year) 1) initially 2) after 2 years b)now suppose that r is increasing by 0.3 per year when r=4 and t=2. At what rate is the price increasing at that time? I can do part a) of this question but cant figure out the solution to part b).

OpenStudy (perl):

inflammation?

OpenStudy (anonymous):

inflation not inflammation sorry

OpenStudy (perl):

b) use product rule

OpenStudy (perl):

show me your work for part a) first

OpenStudy (perl):

nice pic

OpenStudy (anonymous):

dp/dt = 5re^(rt/100) so initially is 5r dollars/year and after 2 years 5re^(r(2)/100)

OpenStudy (perl):

good

OpenStudy (perl):

now suppose r is not constant

OpenStudy (anonymous):

yea what do I do with 0.3

OpenStudy (anonymous):

do I do the dP/dt again with r=0.3?

OpenStudy (anonymous):

what?*

OpenStudy (perl):

so I assumed that r is a function of time

OpenStudy (perl):

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