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Find the square roots of -3+4i
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square roots ?
5.73205081 i according to google :/
i do know if you convert to polar form, r = 5(radius),theta =126.87°(angle)
I haven't learned polar form yet... It's using the (a^2-b^2)+2abi method.
How do you factor a^4+3a^2+4=0?
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i think you cannot factor it ?! (not include using the quadratic formula)
with that you get four roots then
When it's a^4-3a^2-4=0, it factors as (a^2-4)(a^2+1)..?
@order (a^2-a+2) (a^2+a+2) = 0, is a = -3+j4 ?
Not sure... does this have to do with my question?
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yep, yep
(1 + 2i)^2 = -3+4i
|dw:1333533962294:dw| solve that system to get a and b...
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