Convert (1+i)/2 into polar(trigonometric) form. Please see attached possible answers, thanks

Question

amistre64 · Answer

reading complex numbers is similar to reading an ordered pair; it can be thought of as (R,i)

R + bi

amistre64 · Answer

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didee · Answer

Attached are some possible answers. I'm not sure how to get to the answer.

experimentx · Answer

should be $$2\sqrt{2}(\cos \pi/4 + i \sin \pi/4)$$

experimentx · Answer

but i don't see it anywhere

phi · Answer

The magnitude is 
$$ \sqrt{\frac{1}{2^2}+\frac{1}{2^2}} =\frac{\sqrt{2}}{2}$$

didee · Answer

thanks, I dont either. Like I said, not sure how to get to the answer

phi · Answer

The way you get the answer is look at amistre's plot.
Find the length of the hypotenuse using pythagorean theorem
use inverse tangent of opposite/adjacent to find the angle alpha

phi · Answer

the answer is 
$$ \frac{\sqrt{2}}{2}(cos(\frac{\pi}{4}) + i sin(\frac{\pi}{4}) $$

experimentx · Answer

Oo .. it seems that 2 is dividing the ... not multiplying.

didee · Answer

thanks guys, I dont have a clue whats going on and going to struggle in exams. where can I get some lessons/background on this? any website suggestions? also, how do I use wolfram? I've heard about that website.

anonymous · Answer

http://wn.com/The_Polar_Form_of_Complex_Numbers