Question

Solve ln x − ln(x −1)= 1

Answer 1

ln x − ln(x −1)= 1

\[\ln(\frac{x}{x-1})= 1\]
\[\frac{x}{x-1}=e^1\]
x=ex-e

x-ex=-e

x(1-e)=-e

\[x=\frac{-e}{1-e}\]

Answer 2

what formula did you use?

Answer 3

From where to where?

Answer 4

ln x − ln(x −1)= 1

\[\ln(\frac{x}{x-1})= 1\]

Here?

Answer 5

the first step

Answer 6

yes

Answer 7

e^a=b?

Answer 8

See the attachment

Answer 9

oh ok thanx

Answer 10

ln x − ln(x −1)= 1
Using rule , log(m/n) = log(m) – log(n)

\[\ln(\frac{x}{x-1})= 1\]
Exponent both sides,
\[e^{\ln(\frac{x}{x-1})}=e ^{1}\]
\[\frac{x}{x-1}=e^1\]
x=ex-e

x-ex=-e

x(1-e)=-e

\[x=\frac{-e}{1-e}\]