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Use a double integral in polar coordinates to find the area taken up by one petal of the rose curve r = sin 2θ . Please explain step by step
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very nice one lad! first we want to draw this region. then we will see that our integration boundaries should be 0<theta<pi/2 and r is between 0 and sin2theta. thus it would be set up as double integral(sin2theta)rdr dtheta. i rather sure this is how to do it. what ya think?
check this out! http://tutorial.math.lamar.edu/Classes/CalcIII/DIPolarCoords.aspx theres basically an exact example!
@.Sam. what is that graph? looks like r=theta
That seems to be a logarithmic spiral: \[r = e^\theta\]
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(p.s. referring to sam)
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