A diatomic gas molecule has a mass of 9.63 x 10^-26 kg and a rotational inertia of 6.50 x 10^-46 kg·m^2 about an axis through the center of the line joining the atoms and perpendicular to that line. Suppose the center of mass of the molecule has a translational speed of 599 m/s and the molecule has a rotational kinetic energy that is 2/3 of the translational kinetic energy of its center of mass. What then is the molecule's angular speed about the center of mass?

Question

apoorvk · Answer

The time taken to cover the last mile increased from the previous mile, so the speed definitely decreased over there, which is a result of deceleration, or negative acceleration.

Hence, last option!

anonymous · Answer

Translation kinetic energy is defined as$$TKE = {1 \over 2} mv^2$$Rotational kinetic energy is defined as$$RKE = {1 \over 2} I \omega^2$$where $\omega$ is the angular velocity. 
From the problem statement, 
$${2 \over 3} TKE = RKE$$

anonymous · Answer

so m = 9.63 x 10^-26 kg
v = 599 m/s

what is 6.50 x 10^-46 kg·m^2?

anonymous · Answer

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