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With help from Taylor series, expand f(x)=e^(sinx) with a fourth order polynomial by substituting the expanding of sinx in the expansion by e^x. Completely mega stuck. :(
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which you have to make an expantion , 0?
i mean which point, sry
Maclaren?
Indeed!
so i guess this thing that says :" substituting the expanding of sinx in the expansion by e^x" might mean that x and sinx are equivalent if you are close enough to 0. So I would guess what you need to do is just expand a e^x. Not sure....
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Think I figured it out, thanks! 1+x+x^2/2-x^4/8 Not 100% though, all the solving/writing is making my fingers go numb, hehe.
ya, thats e^x expansion
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