Question

f(x) = e^(2x+1).sin(2x+1)

Answer 1

what about it?

Answer 2

how do you simplify it?

Answer 3

I'm meant to be using calculus' product rule. I get so far then I get stuck when it comes to factoring.

Answer 4

I don't think you can simplify this further, you can write the sine as the sum of two complex powers of e, but that doesn't get you any further.

Answer 5

You're saying the product rule, so you need to differentiate?

Answer 6

yes

Answer 7

I can differentiate it but struggle when it comes to factoring.

Answer 8

I get up to, sin(2x+1).2e^(2x+1) + e^(2x+1)2cos(2x+1) and then I'm stuck.

Answer 9

that's good so far, both terms have the factor 2e^(2x+1), you can take that out.

Answer 10

So 2e^(2x+1)(sin(2x+1)+cos(2x+1))

Answer 11

Thanks @Thomas9