Question

find the laplace transforms when f(t)=e^(6t) if 05 Can anyone help?

Answer 1

\[\large\left.L\{e^{6t}\}\right|_{0}^{5}+\left.L\{1\}\right|_{5}^{inf}\]

Answer 2

\[e^{6t}\to\ e^{(6-s)t} =\frac{e^{(6-s)5}}{6-s}-\frac{e^{(6-s)0}}{6-s}\]\[1\to\ e^{-st} =\frac{e^{-sinf}}{-s}-\frac{e^{-s5}}{-s}\]

Answer 3

isnt e^-sinf be equal to zero then?

Answer 4

yes, unless theyve altered reality when i wasnt looking :)

Answer 5

so the answer would be e^((6-s)5)/(6-s)-1/(6-s)+e^(-s5)/s would that be correct?

Answer 6

that last bit should be a -

and you might wana simplify for good measure; but yes

Answer 7

i see, you took the - from teh s .. ok

Answer 8

well you are deviding by -s so itd be positive. Thanks for the help though! :) It is greatly appreciated :)

Answer 9

yw :)