Question

∫ (3x²+4-2)dx
Can anyone walk me through this?

Answer 1

the answer is 6x

Answer 2

if u take the derivative of 4dx - 2dx u'll get nothing

Answer 3

∫ (3x²+4-2)dx
= ∫ (3x²+2)dx
= 3(1/3)x^3 +2(x) +c
= x^3 +2x +c

Answer 4

i doubt if your question is ∫ (3x²+4x-2)dx ...

Answer 5

gahh damnit i mistyped the problem. supposed to be +4x not +4. Sorry

Answer 6

oh so its 6x+4

Answer 7

\[\int (3x²+4-2)dx =\frac{3x^{2+1}}{2+1}+\frac{4x^{1+1}}{1+1}-2x^{0+1}\]
\
\[=x^3+2x^2-2x\]

Answer 8

∫ (3x²+4x-2)dx

thats what the problem should look like

Answer 9

satellite73 helps you solve your problem :)

Answer 10

Thanks for the help everyone